64x^2+x^2=-16x^2+x+63

Solution for 64x^2+x^2=-16x^2+x+63 equation:

64x^2+x^2=-16x^2+x+63

We move all terms to the left:

64x^2+x^2-(-16x^2+x+63)=0

We add all the numbers together, and all the variables

65x^2-(-16x^2+x+63)=0

We get rid of parentheses

65x^2+16x^2-x-63=0

We add all the numbers together, and all the variables

81x^2-1x-63=0

a = 81; b = -1; c = -63;
Δ = b2-4ac
Δ = -12-4·81·(-63)
Δ = 20413
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{20413}}{2*81}=\frac{1-\sqrt{20413}}{162}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{20413}}{2*81}=\frac{1+\sqrt{20413}}{162}
$